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2 February, 11:04

A series combination of two resistors of resistance 12 Ω and 8 Ω is connected across a source of emf 24 V. What is the potential difference across 8 Ω resistors?

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  1. 2 February, 12:56
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    The Potential difference across the 8 Ω resistor = 9.6 V

    Explanation:

    In a series combination of resistor, The total resistance

    Rt = R₁ + R₂ ... Equation 1

    Where Rt = total resistance, R₁ = Resistance of the first resistor, R₂ = resistance of the second resistor.

    Given: R₁ = 12Ω, R₂ = 8Ω.

    Substituting these vales into equation 1

    Rt = 12 + 8

    Rt = 20 Ω.

    Since both resistors are connected in series, The same current flows through both resistors.

    from ohms law,

    V = IR ... Equation 3

    I = V/R ... Equation 2

    where I = current flowing through both resistors, V = Emf, R = total resistance of the circuit

    Also given : V = 24 V, R = 20 Ω,

    Substituting these values into equation 3,

    I = 24/20

    I = 1.2 A.

    Note: Since both resistors are connected in series, The same current flows through both resistors.

    The Potential difference across the 8 Ω resistor

    V = 1.2*8

    V = 9.6 V

    The Potential difference across the 8 Ω resistor = 9.6 V
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