A uniform steel beam has a mass of 1800 kg. on it is resting half of an identical beam, as shown in fig. 9-44. what is the vertical support force at each end? left end n (upward) right end n (upward)

Question

Amour

Physics

12 April, 19:07

A uniform steel beam has a mass of 1800 kg. on it is resting half of an identical beam, as shown in fig. 9-44. what is the vertical support force at each end? left end n (upward) right end n (upward)

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Cassidy Mcgrath · Answer 1

Let the left end A and the right end B.

Let w = the weight of the full beam.

0 = - (w/2) * (L/4) - (w) * (L/2) + Fa*L

Fa = [ (w/2) * (L/4) + (w) * (L/2) ]/L = w/8 + w/2 = 5/8*w = 5/8*m*g = 5/8*1800*9.81 Fa = 11036.25 N

Fa + Fb = w Fb = w - Fa = 1.8 * (1800*9.81) - 11036.25 Fb = 20748.15 N