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24 November, 09:58

If a taxi moves with an initial velocity of + 12.6 meters/second and has a constant acceleration of + 3.1 meters/second2, what is its final velocity after 6.0 seconds?

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  1. 24 November, 10:21
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    'Acceleration' of 3.1 m/s² means that the taxi is speeding up, and

    it's speed is 3.1 m/s faster each second than it was a second earlier.

    So, after 6.0 seconds, its speed is (6 x 3.1) = 18.6 m/s faster than

    it was at the beginning of the 6 seconds.

    That speed was 12.6 m/s when the 6 seconds began, so it's

    (12.6 + 18.6) = 31.2 m/s

    at the end of the 6 seconds.

    Notice that this whole discussion talks about the taxi's speed, not velocity ...

    just as the question should. There isn't a single word anywhere in the

    question that refers to the taxi's direction, so we don't have a shred of

    information that would make it possible to say anything about its velocity.
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