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10 December, 08:30

Carlotta does 2000 j of work on a machine. The machine does 500 J of work what is the efficiency of this machine

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  1. 10 December, 08:42
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    Efficiency of a machine = (useful output energy) / (total input energy)

    Efficiency = (500 J output work) / (Carlotta's 2,000 J input work)

    Efficiency = (500 J) / (2,000 J)

    Efficiency = 0.25

    Efficiency = 25%
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