A 1400-kg car traveling east at 25m/s collides with a 1800-kg car traveling at a speed of 20m/s in a direction that makes angle of 40degree south of west. the cars stick together after the collision. what is the magnitude and direction of the velocity of the cars after the collision?

Question

Cherish Boone

Physics

30 September, 04:29

A 1400-kg car traveling east at 25m/s collides with a 1800-kg car traveling at a speed of 20m/s in a direction that makes angle of 40degree south of west. the cars stick together after the collision. what is the magnitude and direction of the velocity of the cars after the collision?

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Lydia Ferguson · Answer 1

M1*V1 + M2*V2 = M1*V + M2*V.

1400*25 + 1800*20[180+40]=1400*V+1800*V.

Divide both sides by 100:

14*25 + 18*20[220o] = 14V + 18V.

350 + 360[220o] = 32V.

350 - 276-231i = 32V.

74 - 231i = 32V.

242.6[-72.2o] = 32V.

V = 7.6m/s[-72.2o]=7.6m/s[72o] S. of E.