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9 January, 00:20

a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the water how far away from the edge of the board will they land?

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  1. 9 January, 00:44
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    2.846m

    Explanation:

    The diver is performing projectile motion.

    To find x (final), we are going to use the equation x (final) = v (initial) * t + x (initial)

    x (initial) = 0

    x (final) = ?

    v (initial) = 2.3 m/s

    we don't know t

    To find t we will use y (final) = 1/2 * (-9.8) * t^2 + v (initial in the y dir.) * t + y (initial)

    - 9.8 in the acceleration in the y dir.

    y (final) = 0

    y (initial) = 7.5

    v (initial in the y dir.) = 0

    If we solve for t we get: t = 1.237s

    Now we have all the components to solve for x (final) in x (final) = v (initial) * t + x (initial)

    x (final) = 2.3*1.237 + 0

    x (final) = 2.846m
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