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17 March, 08:36

A 1.2 kg ball drops vertically onto a floor, hitting with a speed of 20 m/s. it rebounds with an initial speed of 5.6 m/s. (a) what impulse acts on the ball during the contact

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  1. 17 March, 08:40
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    The force acting on the ball is the same than the ball acts on the floor at the moment of hitting but in the reverse direction. So the ball produces a force downwards and the floor makes the same force in value but upwards. Then the value of the force that impulses the ball upward is: F = m * a where F is force or impulse, m is mass of the ball and a is acceleration (9.8 m/s2) F = 1.2 kg * 9.8 m/s2 = 11.76 kg*m/s2 = 11.76 Newtons (upwards)
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