In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied over the same distance. Which shopping cart has more KE by the time it gets to the end of the course?

A. cart A

B. cart B

C. neither, they have the same KE

Question

Zane Mccormick

Physics

7 February, 20:27

In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied over the same distance. Which shopping cart has more KE by the time it gets to the end of the course?

A. cart A

B. cart B

C. neither, they have the same KE

+5

Answers (1)

Know the Answer?

Franco Reese · Answer 1

K = 1/2 m x v^2

m = mass on the cart

V = velocity imparted to the cart

KA = 1/2 mA x vA^2 ... (1)

KB = 1/2 mB x vB^2 ... (2)

Diving equation 1 by equation 2, we get -

KA/KB = mA/mB

= 2

KA = 2 x KB

Option A is correct

In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied over the same distance. Which shopping cart has more KE by the time it gets to the end of the course?A. cart AB. cart BC. neither, they have the same KE

In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied over the same distance. Which shopping cart has more KE by the time it gets to the end of the course?

A. cart A

B. cart B

C. neither, they have the same KE