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12 May, 00:59

One end of a steel rod of radius R = 10 mm and length L = 80cm is held in a vise. A force of magnitude F = 60kN is then applied perpendicularly to the end face (uniformly across the area) at the other end, pulling directly away from the vise. What is the stress on the rod?

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  1. 12 May, 01:28
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    Answer: 1.91*10^8 N/m²

    Explanation:

    Given

    Radius of the steel, R = 10 mm = 0.01 m

    Length of the steel, L = 80 cm = 0.8 m

    Force applied on the steel, F = 60 kN

    Stress on the rod, = ?

    Area of the rod, A = πr²

    A = 3.142 * 0.01²

    A = 0.0003142

    Stress = Force applied on the steel/Area of the steel

    Stress = F/A

    Stress = 60*10^3 / 0.0003142

    Stress = 1.91*10^8 N/m²

    From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²
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