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17 January, 00:19

Problem 20.75 A thin rectangular coil 2 cm by 9 cm has 44 turns of copper wire. It is made to rotate with angular frequency 110 rad/s in a magnetic field of 1.9 T. (a) What is the maximum emf produced in the coil? V (b) What is the maximum power delivered to a 50 ohm resistor? W

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  1. 17 January, 00:29
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    (a) 16.5528 V

    (b) 827.64 W

    Explanation:

    (a)

    The formula for maximum emf produced in a coil is given as

    E₀ = BANω ... Equation 1

    Where E₀ = maximum emf produced in the coil, B = magnetic Field, A = Area of the rectangular coil, N = number of turns, ω = angular velocity.

    Given: B = 1.9 T, N = 44 turns, ω = 110 rad/s, A = 2*9 = 18 cm² = 18/10000 = 0.0018 m²

    Substitute into equation 1

    E₀ = 1.9 (44) (110) (0.0018)

    E₀ = 16.5528 V

    (b)

    Maximum power

    P₀ = E₀²/R ... Equation 2

    Where R = Resistance.

    Given: R = 50 ohms, E₀ = 16.5528 V

    Substitute into equation 2

    P₀ = 50 (16.5528)

    P₀ = 827.64 W
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