Consider two cylindrical conductors made of the same ohmic material. v1 ~e1 i1 ℓ1 r1 b v2 ~e2 i2 ℓ2 r2 b if rho2 = rho1, r2 = 2 r1, ℓ2 = 2 ℓ1, and v2 = v1, find the ratio r2 r1 of the resistances

3/4

Explanation:

Here is the complete question

Consider two cylindrical conductors made of the same ohmic material. If ρ2 = ρ1, r2 = 2 r1, ℓ2 = 3 ℓ1, and V2 = V1, find the ratio R2 R1 of the resistances

Resistance, R = ρl/A where ρ = resistivity, l = length and A = area

For cylinder 1, R₁ = ρ₁l₁/A₁

For cylinder 2, R₂ = ρ₂l₂/A₂

ρ₂ = ρ₁, l₂ = 3l₁, r₂ = 2r₁ where r₁ and r₂ are the radii of the cylinders.

R₂/R₁ = ρ₂l₂/A₂ : ρ₁l₁/A₁

= ρ₂l₂A₁/ρ₁l₁A₂

= ρ₂l₂πr₁²/ρ₁l₁πr₂²

= ρ₂l₂r₁²/ρ₁l₁r₂²

substituting the required values

= ρ₁ * 3l₁ * r₁²/ρ₁ * l₁ * (2r₁) ²

R₂/R₁ = 3/4