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12 May, 08:55

A toy train rolls around a horizontal 1.0-m-diameter track. the coefficient of rolling friction is 0.10. how long does it take the train to stop if it's released with an angular speed of 40 rpm?

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  1. 12 May, 09:16
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    Deceleration due to rolling resistance (α) = coefficient*g/R = 0.1*9.81/0.5 = 1.962 rad/sec^2

    Equations of motion:

    ωf=ωo+αt

    But ωf = 0 rad/sec; ωo = 2*pi*RPM/60 = 4.19 rad/sec

    Therefore,

    0=4.19-1.962t = > 1.962t = 4.19 = > t = 4.19/1.962 = 2.13 seconds
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