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25 July, 12:03

A man takes a brick out of the fire when it's at 285 degree Celsius, he drops it in a bucket of water. then covers the bucket. the bucket and cover are made of an insulating material. the bucket contains 2.6 kg of ice originally at - 5 degree celsius. the 1.3 kg brick is made of iron. which has a specific heat of 448J/kg degree celsius. lets find out the temperature of brick and water once equilibrium is reached. specific heats of ice, liquid water, steam are 2090,4186,1970 respectively

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  1. 25 July, 12:12
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    Answer: The equilibrium temperature of brick and water is 2.82 Kelvin

    Explanation:

    Initial Temperature Ø of the brick = 285 degree Celsius

    Initial temperature of ice = - 5 degree Celsius

    Mass of iron = 1.3kg

    Specific heat capacity c of iron = 448J/kg

    In thermal experiments,

    Heat lost = heat gain.

    Let's first calculate the heat lost

    The brick will loose heat.

    H = mcØ

    Heat lost = 1.3 * 448 * (285 - T)

    Heat lost = 582.4 (285 - T)

    Now let's calculate for heat gain

    Heat gain = mcØ + mcØ + mcØ

    Heat gain = [ (2.6*2090) + (2.6*4186) + (2.6*1970) ] (T - - 5)

    Heat gain = 5434 + 10883.6 + 5122 (T+5)

    Heat gain = 21439.6 (T + 5)

    Equating the heat lost and the heat gain leads to

    582.4 (285 - T) = 21439.6 (T+5)

    Open both bracket

    165984 - 582.4T = 21439.6T + 107198

    Collect the like terms

    21439.6T - 582.4T = 165984 - 107198

    20857.2T = 58786

    T = 58786/20857.2

    T = 2.82 Kelvins

    The equilibrium temperature of brick and water is 2.82 Kelvin
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