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21 April, 20:33

A 21.6-kg cube made from aluminum is at its melting temperature of 660℃. If you were to add 8000 kJ worth of energy as heat, what percent of the block melts? You might need the following: α = 23.0 ✕ 10-6 K-1, β = 69.0 ✕ 10-6 K-1, c = 900 J/kgK, LF = 3.98 ✕ 105 J/kg

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  1. 21 April, 20:39
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    The percentage of block melts is 93.1 %

    Explanation:

    Let the block melted be m₁

    Given: LF = 3.98 * 10⁵ J/kg

    Amount of heat added, Q = 8000 KJ = 8*10⁶ J

    Using:

    Q = m₁*LF

    8*10⁶ = m₁ * 3.98 * 10⁵

    m₁ = 20.1 kg

    So, the percentage of block melts, % = m₁/m * 100

    % = 20.1 / 21.6 * 100 = 93.1 %

    The percentage of block melts is 93.1 %
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