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28 May, 23:37

Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hourmiles/hour in 2.22 ss starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared. Ente

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  1. 28 May, 23:44
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    The acceleration of the cheetahs is 10.1 m/s²

    Explanation:

    Hi there!

    The equation of velocity of an object moving along a straight line with constant acceleration is the following:

    v = v0 + a · t

    Where:

    v = velocity of the object at time t.

    v0 = initial velocity.

    a = acceleration.

    t = time

    We know that at t = 2.22 s, v = 50.0 mi/h. The initial velocity, v0, is zero.

    Let's convert mi/h into m/s:

    50.0 mi/h · (1609.3 m / 1 mi) · (1 h / 3600 s) = 22.4 m/s

    Then, using the equation:

    v = v0 + a · t

    22.4 m/s = 0 m/s + a · 2.22 s

    Solving for a:

    22.4 m/s / 2.22 s = a

    a = 10.1 m/s²

    The acceleration of the cheetahs is 10.1 m/s²
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