A crane carries a 1600 kg car at 1.5 m/s^2 with a chain that has a negligible mass. If the coefficient of kinetic friction between the wheels of the car and the road is 0.3, what is the tension in the chain? a. 3.8 kN

b. 5.9 kN

c. 6.7 kN

d. 7.1 kN

option (d) 7.1 kN

Explanation:

Given:

Mass of the car, m = 1600 kg

Acceleration of the car, a = 1.5 m/s²

Coefficient of kinetic friction = 0.3

let the tension be 'T'

Now,

ma = T - f ... (1)

where f is the frictional force

also,

f = 0.3 * mg

where g is the acceleration due to the gravity

thus,

f = 0.3 * 1600 * 9.81 =

therefore,

equation 1 becomes

1600 * 1.5 = T - 4708.8

or

T = 2400 + 4708.8

or

T = 7108.8 N

or

T = 7.108 kN

Hence,

The correct answer is option (d) 7.1 kN