A morsel of food with a mass of 3.8 g is injected into the esophagus with an initial speed of 2.2 cm/s. On the way down to the stomach, the walls of the esophagus exert an upward resistive force of 2.7 ✕ 10-3 N on the morsel. If the esophagus is 19.4 cm long, with what speed does the morsel of food enter the stomach?

Question

Cameron Bryan

Physics

24 November, 02:43

A morsel of food with a mass of 3.8 g is injected into the esophagus with an initial speed of 2.2 cm/s. On the way down to the stomach, the walls of the esophagus exert an upward resistive force of 2.7 ✕ 10-3 N on the morsel. If the esophagus is 19.4 cm long, with what speed does the morsel of food enter the stomach?

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Zoie Hansen · Answer 1

mass m = 3.8 g

= 3.8 x 10⁻³ kg

force = 2.7 x 10⁻³N

acceleration = - 2.7 x 10⁻³ / (3.8 x 10⁻³)

a = -.7105 m / s²

= 71.05 cm/s²

v² = u² - 2 a s

= 2.2² - 2 x 71.05 x 19.4

= 4.84 - 2756.74

= - 2751.9

= - 2752 cm / s

Since it is negative that means, resistive force will not allow it to enter esophagus. It will be going in upward direction.

It appears that there is something wrong with given data.