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11 August, 02:02

A 4 kg block slides down a rough inclined plane inclined at 30° 179009. GIF with the horizontal. Determine the coefficient of kinetic friction between the block and the surface if the block has an acceleration of 1.2 m/s2.

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  1. 11 August, 02:17
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    F=ma

    F = 4x1.2

    F = 4.8 N

    F = 4gsin30 - Friction

    Friction = 19.6 - 4.8 N

    Friction = 14.8 N

    Friction = u x 4gcos30

    14.8 / 4gcos30 = u

    u = 0.43596 ...

    u = 0.44

    coefficient is 0.44
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