A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether or not you got a bargain, so you lower the statue into a container of water and measure the volume of displaced water.

A) Find the volume of water that will be displaced for pure gold.

B) For my answer I found 51813 kg/m^3. It marked me down saying enter your answer using dimension of volume ... i thought kg/m^3 was dimesnsion of volume?

Question

Sundance

Physics

28 June, 06:31

A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether or not you got a bargain, so you lower the statue into a container of water and measure the volume of displaced water.

A) Find the volume of water that will be displaced for pure gold.

B) For my answer I found 51813 kg/m^3. It marked me down saying enter your answer using dimension of volume ... i thought kg/m^3 was dimesnsion of volume?

+2

Answers (1)

Know the Answer?

Vincent Weber · Answer 1

a) 51.8 cm³

b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.

Explanation:

a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)

V = 1000/19.3

V = 51.8 cm³