Starting from the front door of your ranch house, you walk 50.0m due east to your windmill, and then you turn around and slowly walk 30.0m west to a bench where you sit and watch the sunrise. It takes you 27.0s to walk from your house to the windmill and then 39.0s to walk from the windmill to the bench. For the entire trip from your front door to the bench, what is your average velocity? For the entire trip from your front door to the bench, what is your average speed?

Question

Jayvion Beltran

Physics

27 May, 19:29

Starting from the front door of your ranch house, you walk 50.0m due east to your windmill, and then you turn around and slowly walk 30.0m west to a bench where you sit and watch the sunrise. It takes you 27.0s to walk from your house to the windmill and then 39.0s to walk from the windmill to the bench. For the entire trip from your front door to the bench, what is your average velocity? For the entire trip from your front door to the bench, what is your average speed?

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Answers (1)

Know the Answer?

Conner Scott · Answer 1

velocity = 0.3m/s

speed = 1.21 m/s

Explanation:

The total time it takes to get from the front door to the bench is

t = 27 + 39 = 66 seconds

The net displacement from the front door to the bench is the distance from the front door to the windmill subtracted by the distance from the windmill to the bench

s = 50 - 30 = 20 m

So the average velocity is net displacement divided by total time

v = s / t = 20 / 66 = 0.3 m/s

The total distance from the front door to the bench is the sum of distance from the front door to the windmill and the distance from the windmill to the bench

S = 50 + 30 = 80 m

So the average speed is total distance divided by total time

v = s / t = 80 / 66 = 1.21 m/s