What must be the contact area between a suction cup (completely exhausted) and a ceiling in order to support the weight of a 54.3 kg student? the acceleration of gravity is 9.8 m/s 2?

Question

Andres Pineda

Physics

4 January, 05:21

What must be the contact area between a suction cup (completely exhausted) and a ceiling in order to support the weight of a 54.3 kg student? the acceleration of gravity is 9.8 m/s 2?

+1

Answers (1)

Know the Answer?

Drew · Answer 1

But it all comes from the equation of pressure: P = F / S

P = Pressure, in Pascal, [P]

F = Force, in Newton [N]

S = Surface, in squared meters [S]

Atmospheric pressure * area = weight

101325 pascal * area = 54.3 pascal * 9.8 N

= 532.14 kg^2 converting this to m, it will be 0.0053 m^2