1. Calculate the total heat content of 10 kg of ice at - 23°C.?

2. How much heat is contained in 100 kg of water at 60.0 °C?

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) (2090 J / Kg C) (-23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) (4180 J/kg C) (60 C)

H = 2508000 J