A 60 kg man jumps down from a 0.8 m table. What is the speed when he

hits the ground? (Take g = 10 m/s2)

Answer: Speed = 4 m/s

Explanation:

The parameters given are

Mass M = 60 kg

Height h = 0.8 m

Acceleration due to gravity g = 10 m/s2

Before the man jumps, he will be experiencing potential energy at the top of the table.

P. E = mgh

Substitute all the parameters into the formula

P. E = 60 * 9.8 * 0.8

P. E = 470.4 J

As he jumped from the table and hit the ground, the whole P. E will be converted to kinetic energy according to conservative of energy.

When hitting the ground,

K. E = P. E

Where K. E = 1/2mv^2

Substitute m and 470.4 into the formula

470.4 = 1/2 * 60 * V^2

V^2 = 470.4/30

V^2 = 15.68

V = square root (15.68)

V = 3.959 m/s

Therefore, the speed of the man when hitting the ground is approximately 4 m/s