How much heat must be absorbed by 375 grams of water to raise its temperature by 25°c

the formula q = 375 g * 25 C * 4.186 J / (g*C) = 39,243.75 J q represents the heat in Joules, m the mass in grams, difference of temperature in Celsius degree, and 4.186 J / (g*C) is the specific heat of water (I assume the water is in liquid from and will remain liquid). Approximately 39.24 kJ once you round and transform to kJ ... 1 kJ=1000J