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3 November, 21:01

A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force on the skydiver?

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  1. 3 November, 21:06
    0
    497.6 N

    Explanation:

    From the question,

    The net force on the skydiver = weight of the skydiver - the resistive force of air

    F' = W-F ... Equation 1

    Where W = weight of the skydiver, F = resistive force of air.

    But,

    W = mg ... Equation 2

    Where m = mass of the skydiver, g = acceleration due to gravity.

    Substitute equation 2 into equation 1

    F' = mg-F ... Equation 3

    Given: m = 87 kg, F = 355 N, g = 9.8 m/s²

    Substitute these values into equation 3

    F' = 87 (9.8) - 355

    F' = 852.6-355

    F' = 487.6 N
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