As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06

Question

Allan Flynn

Physics

2 April, 16:21

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06

+5

Answers (1)

Know the Answer?

Chloe Arnold · Answer 1

The equation for the index of refraction is n = sin (theta1) / sin (theta2) where theta1 is the refracted angle and theta2 is the angle in a medium. Plugging in the values for the index of refraction, n = sin (32) / sin (26) we get 1.21. the answer is letter C. The index of refraction is always greater than 1.

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?A) 0.827B) 0.944C) 1.21D) 1.06

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06