Ask Question
29 May, 01:10

The magnetic field between the poles of a magnet has magnitude 0.510 T. A circular loop of wire with radius 3.20 cm is placed between the poles so the field makes an angle of 22.0° with the plane of the loop. What is the magnetic flux through the loop?

+2
Answers (2)
  1. 29 May, 01:12
    0
    The magnetic flux through the loop is 0.00478 T. m²

    Explanation:

    Given;

    magnitude of magnetic field, B = 0.510 T

    radius of the circular loop, r = 3.2cm

    angle between the fields, θ = 22.0°

    Area of the loop:

    A = πr²

    A = π (0.032) ² = 0.0101 m²

    Φ = BAcosθ

    where;

    Φ is the the magnetic flux through the loop

    Φ = BAcosθ

    Φ = 0.51 x 0.0101 x cos22°

    Φ = 0.005151 x 0.9272

    Φ = 0.00478 T. m²

    Therefore, the magnetic flux through the loop is 0.00478 T. m²
  2. 29 May, 01:21
    0
    1.52*10⁻³ Wb

    Explanation:

    Using

    Φ = BAcosθ ... Equation

    Where, Φ = magnetic Field, B = 0.510 T, A = cross sectional area of the loop, θ = angle between field and the plane of the loop

    Given: B = 0.510 T, θ = 22°,

    A = πr², Where r = radius of the circular loop = 3.20 cm = 0.032 m

    A = 3.14 (0.032²)

    A = 3.215*10⁻³ m²

    Substitute into equation 1

    Ф = 0.510 (3.215*10⁻³) cos22°

    Ф = 0.510 (3.215*10⁻³) (0.927)

    Ф = 1.52*10⁻³ Wb

    Hence the magnetic flux through the loop = 1.52*10⁻³ Wb
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The magnetic field between the poles of a magnet has magnitude 0.510 T. A circular loop of wire with radius 3.20 cm is placed between the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers