A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the distance covered in 4 seconds?

Question

Kathleen Cowan

Physics

22 May, 01:47

A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the distance covered in 4 seconds?

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Answers (1)

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Braylon Byrd · Answer 1

Perpendicular acceleration:

F = ma

a = 4 / 2 = 2 m/s²

Perpendicular distance:

s = ut + 1/2 at²

s = 0 x 4 + 1/2 x 2 x 4²

s = 16 m

Horizontal distance:

s = ut

= 3 x 4

= 12 m

Total distance = √ (12² + 16²)

= 20 m.