A sky diver jumps from a reasonable height above the ground. The air resistance she experiences is proportional to her velocity, and the constant of proportionality is k = 0.19. It can be shown that the downward velocity of the sky diver at time t is given by v (t) = A (1 - e^-kt) where t is measured in seconds and v (t) is measured in feet per second (ft/s). Suppose A = 64.

(a) Find the initial velocity of the sky diver.

(b) Find the velocity after 5 s and after 15 s. (Round your answers to one decimal place.) ... ?

Question

Melody Hughes

Physics

18 August, 06:35

A sky diver jumps from a reasonable height above the ground. The air resistance she experiences is proportional to her velocity, and the constant of proportionality is k = 0.19. It can be shown that the downward velocity of the sky diver at time t is given by v (t) = A (1 - e^-kt) where t is measured in seconds and v (t) is measured in feet per second (ft/s). Suppose A = 64.

(a) Find the initial velocity of the sky diver.

(b) Find the velocity after 5 s and after 15 s. (Round your answers to one decimal place.) ... ?

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Answers (1)

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Maeve Mckenzie · Answer 1

The initial velocity of the sky diver would be t=0. So put that into the equation:

v (0) = 64 (1 - e (-0.19) (0))

and for b it will be

(5) = 64 (1 - e (-0.19) (5)), and likewise for t=15. You just need to throw it in a calculator.