A 143-g sample of mercury is at an initial temperature of 25 °C. If 1067 joules of heat are applied to the sample, what is the final temperature of the mercury? The specific heat capacity of mercury is 0.14 J / (g∙ °C).

Answer: T = 78.3 °C

Explanation: To solve for the final temperature we will use the formula for heat which is Q = mc∆T, where ∆T is expressed as (Final Temperature - Initial Temperature). We will derive the formula to find Final temperature. So the working equation will be the following.

T = (Q / mc) + Ti

= 1067 J / 143 g (0.14 J/g°C) + 25°C

= 78.3 °C