During bicycling, a 70 kg person's body produces energy at a rate of about 500 W due to metabolism, 80% of which is converted to heat. How many

Kilograms of water must the person's body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 24

* 109 1/kg

Question

Amari Aguilar

Physics

17 April, 20:38

During bicycling, a 70 kg person's body produces energy at a rate of about 500 W due to metabolism, 80% of which is converted to heat. How many

Kilograms of water must the person's body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 24

* 109 1/kg

+3

Answers (1)

Know the Answer?

Elliot · Answer 1

It is given that the energy produced by a person's body due to metabolism is at a rate of 500W.

Energy produced by him in 1 hour

= 1800000 J

Of this, 80 % is converted into heat.

Heat energy produced

= 1440000 J = 1.4x10^6

1.44x10^6/2.42x10^6=0.595kg