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19 October, 07:39

A 60 kg student is standing motionless. Approximately how much force is the floor exerting on the student?

A. 60 kg downward

B. 600 N upward

C. 600 N downward

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Answers (1)
  1. 19 October, 08:02
    0
    The normal force is equal in magnitude and opposite in direction to the weight of the student.

    W = m · g = 60 kg · 10 m/s² = 600 N (downward)

    N = - 600 N

    Answer:

    B) 600 N upward.
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