a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 s. What is the acceleration of the car. What is the force of the car moving forward?

Question

Jonathon Schroeder

Physics

14 June, 05:43

a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 s. What is the acceleration of the car. What is the force of the car moving forward?

+4

Answers (1)

Know the Answer?

Polly · Answer 1

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

Acceleration is the rate of change of velocity. It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

Force is calculated by the equation, F = Mass * Acceleration This is based on Newton's second law of motion.

Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 * 3.375 = 5062.5 N