Consider a steel guitar string of initial length l=1.00m and cross-sectional area a=0.500mm2. the young's modulus of the steel is y=2.0*1011n/m2. how far (δl) would such a string stretch under a tension of 1500 n? express your answer in millimeters using two significant figures.

L = 1.00 m, the original length

A = 0.5 mm² = 0.5 x 10⁻⁶ m², the cross sectional area

E = 2.0 x 10¹¹ n/m², Young's modulus

P = 1500 N, the applied tension

Calculate the stress.

σ = P/A = (1500 N) / (0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²

Let δ = the stretch of the string.

Then the strain is

ε = δ/L

By definition, the strain is

ε = σ/E = (3 x 10⁹ N/m²) / (2 x 10¹¹ N/m²) = 0.015

Therefore

δ / (1 m) = 0.015

δ = 0.015 m = 15 mm

Answer: 15 mm