The manufacturer of a 6 V dry-cell flashlight battery says that the battery will deliver 15 mA for 64 continuous hours. During that time the voltage will drop from 6 V to 4 V. Assume the drop in voltage is linear with time. how much energy does the battery deliver in this 64h interval?

Question

Alexandra Sharp

Physics

23 September, 05:12

The manufacturer of a 6 V dry-cell flashlight battery says that the battery will deliver 15 mA for 64 continuous hours. During that time the voltage will drop from 6 V to 4 V. Assume the drop in voltage is linear with time. how much energy does the battery deliver in this 64h interval?

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Answers (1)

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Orlando Hoffman · Answer 1

E = 17,280 J

Explanation:

Since the voltage drops linearly from 6V to 4V, the average is 5V. The energy delivered is.

V is the average of initial and fianl voltage

A is the current passing

t is the time in which current is passed

E=V*A*t = 5*0.015 * (64*3600) = 17,280 J