What is the distance required for a car traveling at 70 m/s and decelerating at 10 m/s^2 to stop?

Answer: 245 m

Explanation: V^2 = Vo^2 + 2. a. d

When the car stops, V = 0.

Therefore, 0^2 = 70^2 + 2. (-10). d

0 = 4900 - 20d

d = 4900/20 = 245m

The answer to your question is: 245 m

Explanation:

data

vo = 70 m/s

vf = 0 m/s

a = 10 m/s²

d = ?

Formula

vf² = vo² + 2ad

d = (vf² - vo²) / 2a

Process

d = (0² - 70²) / 2 (10) substitution

d = 4900 / 20 simplify

d = 245 m