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23 February, 10:57

Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. Express your answer in kilojoules

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  1. 23 February, 10:58
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    That would be 2,800 calories
  2. 23 February, 11:02
    0
    The amount of heat will be equal to Lm.

    Where L is the latent heat of fusion and m is mass of the ice.

    Latent heat of ice = 80cal/g.

    So the amount of heat required here will be 35 * 80cal

    = 2,800 cal.
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