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31 October, 04:19

A particle leaves the origin with an initial velocity of 3.00 m/s in the x direction, and moves with constant acceleration ax = - 2.70 m/s2 and ay = 3.90 m/s2. How far does the particle move in the x direction before turning around?

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  1. 31 October, 04:29
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    1.67 m

    Explanation:

    Ux = 3 m/s, ax = - 2.7 m/s^2, vx = 0

    Let the distance travelled before stopping along x axis is x.

    Use third equation of motion along x axis

    Vx^2 = ux^2 + 2 a x

    0 = 9 - 2 * 2.7 * x

    X = 1.67 m
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