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28 November, 03:32

A high-speed bullet train accelerates and decelerates at the rate of 4 ft/s^2. Its maximum cruising speed is 90 mi/h. Suppose that the train starts from rest and must come to a complete stop n 15 minutes. What is the maximum distance it can travel under these conditions?

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  1. 28 November, 03:52
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    810 000 ft

    Explanation:

    First we convert 90 mi/h to ft/s

    90 mi/h = 90 mi/h * 5280 ft/1 mi * 1 hr/3600 s = 132 ft/s

    To find the distance covered for the train to travel from rest to 132 ft/s we use an equation of linear motion based on the values we have and the measurement we are supposed to find:

    x = 0.5at² [the term for initial velocity is omitted because the train starts

    form rest]

    x = 0.5 * 4 ft/s² * (450 s) ² = 405 000 ft

    The maximum distance will be twice this because the train must reach the maximum velocity and again decelerate to zero.

    distance covered = 2 * 405 000 ft = 810 000 ft =
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