Max is pushing on the edge (2.4 m from the center) of the merry-go-round to make it rotate. maya is riding on the merry-go-round, sitting 1.2 m from the center. if max increases the merry-go-round angular speed from 0.52 rev/s to 1.5 rev/s in 2.2 s, what is the merry-go-round angular acceleration

Question

Makaila Fletcher

Physics

16 October, 00:24

Max is pushing on the edge (2.4 m from the center) of the merry-go-round to make it rotate. maya is riding on the merry-go-round, sitting 1.2 m from the center. if max increases the merry-go-round angular speed from 0.52 rev/s to 1.5 rev/s in 2.2 s, what is the merry-go-round angular acceleration

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Donavan · Answer 1

Firstly, the angular acceleration is independent of where Maya is sitting, or if she's sitting on the merry-go-round at all. Max only has to supply more energy.

Initial angular velocity a1: 0.52 rev/s

Final angular velocity a2: 1.5 rev/s

Tim taken t: 2.2s

Angular acceleration: alpha

Using kinematic equations for angular motion, (a2) = (a1) + alpha*t.

This gives alpha as 0.4454 rev/s^2