For the scenarios in which total internal reflection is possible, rank the scenarios on the basis of the critical angle, the angle above which total internal reflection occurs. At this angle, the refracted ray is at 90 degrees from the normal.

Rank from largest to smallest. To rank items as equivalent, overlap them.

A. n1water=1.33, n2air=1.00

B. n1diamond=2.42, n2air=1.00

C. n1diamond=2.42, n2water=1.33

D. n1benzene=1.50, n2water=1.33

Question

Gemma Huffman

Physics

9 June, 00:53

For the scenarios in which total internal reflection is possible, rank the scenarios on the basis of the critical angle, the angle above which total internal reflection occurs. At this angle, the refracted ray is at 90 degrees from the normal.

Rank from largest to smallest. To rank items as equivalent, overlap them.

A. n1water=1.33, n2air=1.00

B. n1diamond=2.42, n2air=1.00

C. n1diamond=2.42, n2water=1.33

D. n1benzene=1.50, n2water=1.33

+2

Answers (1)

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Ayana · Answer 1

For critical angle C the relation is

SinC = 1 / μ where μ is refractive index of denser medium with respect to rarer medium.

In case of A, refractive index of denser medium with respect to rarer medium. is equal to 1.33 / 1 = 1.33

In case of B, refractive index of denser medium with respect to rarer medium. is equal to 2.42 / 1 = 2.42

In case of C, refractive index of denser medium with respect to rarer medium. is equal to 2.42 / 1.33 = 1.82

In case of D, refractive index of denser medium with respect to rarer medium. is equal to 1.50 / 1.33 = 1.127

In case of D, refractive index is lowest, critical angle will be highest.

In case of B, refractive index of denser medium with respect to rarer medium. is highest so critical angle will be lowest.

Ranking from largest to smallest

D > A >C >B.