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23 October, 07:58

A girl pushes a 10.0kg sled at a constant speed by applying a force of 75N at an angle of 30 degrees with respect to the horizontal. The sled is pushed over a distance of 15 meters. How much work is done by the force of friction?

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  1. 23 October, 08:34
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    Answer

    given,

    mass of sled = 10 Kg

    Force applied by girl = ?

    angle of inclination = 30°

    distance = 15 m

    Sled is moving with constant speed hence acceleration will be equal to zero.

    now,

    F - mg sin θ - f = m a

    F - mg sin θ - f = 0

    F - mg sin θ = f

    where f is the frictional force acting opposite to the applied force

    mg sin θ is the component of the weight which is opposing the motion of the sled

    now,

    f = F - mg sin θ

    f = 75 - 10 x 9.8 x sin 30°

    f = 26 N

    now,

    Work done = f. s cos ∅

    where ∅ is the angle between frictional force and displacement which is equal to 180°

    W = 26 x 15 x cos 180°

    W = - 390 J

    work done by frictional force is equal to W = - 390 J
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