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11 February, 06:28

a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 x 10^1 meters per second^2. How long will it take the rocket to reach an altitude of 9.0 x 10^3 meters?

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  1. 11 February, 06:43
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    Here's the formula for the distance covered by an accelerating body in some amount of time ' T '. This formula is incredibly simple but incredibly useful. It pops up so often in Physics that you really should memorize it:

    D = 1/2 a T²

    Distance = (1/2) · (acceleration) · (time²)

    This question gives us the acceleration and the distance, and we want to find the time.

    (9,000 m) = (1/2) (20 m/s²) (time²)

    (9,000 m) = (10 m/s²) (time²)

    Divide each side by 10 m/s²:

    (9,000 m) / (10 m/s²) = (time²)

    900 s² = time²

    Square root each side:

    T = 30 seconds
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