Ask Question
14 December, 19:31

An object of mass 12.0 kg is placed on the pan of a spring-powered scale. The spring constant of the scale is 31.3 N/cm. What distance will the spring be compressed?

+5
Answers (1)
  1. 14 December, 19:43
    0
    F = mg = 12x9.8 = 117.6N. According to Hooke's law, F = kx. x = F/k = 117.6/31.3 = 3.75cm. So compression in the spring is 3.75cm.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An object of mass 12.0 kg is placed on the pan of a spring-powered scale. The spring constant of the scale is 31.3 N/cm. What distance will ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers