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11 August, 18:53

An object is dropped from 26 feet below the tip of the pinnacle atop a 702 ft tall building. The height h of the object after t seconds is given by the equation h=-16t^2+676. Find how many seconds pass before the object reaches the ground.

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  1. 11 August, 19:05
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    6.5 seconds.

    Explanation:

    Given: h=-16t²+679

    When the object reaches the ground, h=0.

    ∴ 0=-16t²+679

    collecting like terms,

    ⇒ 16t²=679

    Dividing both side of the equation by the coefficient of t² i. e 16

    ⇒ 16t²/16 = 679/16

    ⇒ t² = 42.25

    taking the square root of both side of the equation.

    ⇒ √t² = √42.25

    ⇒ t = 6.5 seconds.
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