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16 September, 17:06

A pipe of length 6.8 m is closed at one end and sustains a standing wave at its second overtone. determine the distance between a node and an adjacent antinode.

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  1. 16 September, 17:19
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    For a pipe closed at one end, the second overtone is the 3rd natural frequency as shown in the diagram.

    For the fundamental frequency,

    λ = 4L

    where

    λ = wavelength

    L = the length of the tube

    For the second overtone (3rd frequency)

    λ = (4/3) L

    Because L = 6.8 m, therefore

    λ = (4/3) * (6.8 m) = 9.0667 m

    The distance between a node and an adjacent antinode is λ/2, which is

    9.0667/2 = 4.533 m

    Answer: 4.5 m
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