A 95-kilogram student climbs 4.0 meters up a rope in 3.0 seconds. what is the power output of the student

Given: Mass m = 95 Kg; Height h = 4.0 m; Time t = 3.0 s

Required: Power output

Formula: P = W/t. but Work = Force x distance Force = mg

Distance is equal to Height h

P = mgh/t

P = (95 Kg) (9.8 m/s²) (4.0 m) / 3.0 s

P = 1,242.33 J/s

P = 1.66 Horsepower