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3 August, 23:40

A boy throws a rock with an initial velocity of at 30.0° above the horizontal. If air resistance is negligible, how long does it take for the rock to reach the maximum height of its trajectory?

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  1. 3 August, 23:42
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    Answer: 0.5m/s

    This value may vary depending on the initial velocity value.

    Explanation:

    The question is incomplete due to absence of the initial velocity (U) of the rock. Taking the initial velocity as any value say 10m/s at 30° above the horizontal.

    Time it will take to reach maximum height (Tmax) will be Usin (theta) / g

    Where U is the initial velocity = 10m/s theta = 30° g is the acceleration due to gravity = 10m/s²

    Substituting the values in the formula we have;

    Tmax = 10sin30°/10

    Tmax = sin 30°

    Tmax = 0.5second

    Therefore, it will take for the rock 0.5s to reach the maximum height of its trajectory if the velocity is 10m/s.

    The time varies though depending on the value of the initial velocity.
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