Ask Question
21 February, 08:56

The height of an object dropped from the top of a 64-foot building is given by h (t) = -16t^2+64. How long will it take the object to hit the ground?

+1
Answers (1)
  1. 21 February, 09:07
    0
    1.86 s

    Explanation:

    Given the expression

    h (t) = - 16t² + 64 ... Equation 1

    Where h = height of the object, t = time it will take the object to hit the ground.

    Given: h = 64 foot.

    We have to concert from foot to meters

    If 1 foot = 0.3048 meters

    Then, 64 foot = 0.3048*64 = 19.51 meters.

    We substitute the value of h into equation

    119.51 = - 16t²+64

    -16t² = 199.51-64

    -16t² = 55.51

    t² = 55.51/-16

    t² = 3.469

    t = √3.469

    t = 1.86 s.

    Hence it will take the object 1.86 s to hit the ground.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The height of an object dropped from the top of a 64-foot building is given by h (t) = -16t^2+64. How long will it take the object to hit ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers