When a single high-resistance (long) bulb is connected to a 1.5 volt battery, the current through the battery is about 80 milliampere. If you add another high-resistance (long) bulb in parallel, the battery current of course increases to 160 milliampere. Select all of the true statements given this situation.

a. The battery is ohmic.

b. The battery is not ohmic.

c. Current through the battery is proportional to ΔV across the battery.

d. Current through the battery is not proportional to ΔV across the battery.

e. The battery always puts out the same current.

Question

Leonard Mckenzie

Physics

20 October, 06:57

When a single high-resistance (long) bulb is connected to a 1.5 volt battery, the current through the battery is about 80 milliampere. If you add another high-resistance (long) bulb in parallel, the battery current of course increases to 160 milliampere. Select all of the true statements given this situation.

a. The battery is ohmic.

b. The battery is not ohmic.

c. Current through the battery is proportional to ΔV across the battery.

d. Current through the battery is not proportional to ΔV across the battery.

e. The battery always puts out the same current.

+3

Answers (1)

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Kianna Owens · Answer 1

When two similar resistances are joined parallel to each other, current becomes two times. It is as per ohm's law. On joining in parallel two equal resistances, total resistances of circuit become half. Hence as per ohm's law, current becomes double. Hence the given resistance is ohmic.

Current through the battery will be same as external current in the circuit. Let it be I. Let the external resistance be R. Let the emf of the battery be E. Potential difference on the battery

ΔV = E - IR

If I increases ΔVdecreases. So there is inverse relation.

Option D is correct.

So option A and D are correct.